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Complete the following equation, ${Al}_{2} O_{3} (s) + 2 NaOH (aq) + 3 H_{2} O (l) ⟶ \dots A \dots$ Here, A refers to

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${Al}_{2} O_{3}$

$2 Na [Al (OH)_{4}] (aq)$

${Al}_{2} O_{3} \cdot {xH}_{2} O$

${Na}_{2} [Al (OH)_{4}]$

answer is A.

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${Al}_{2} O_{3} (s) + 2 NaOH (aq) + 3 H_{2} O (l) ⟶ 2 Na [Al (OH)_{4}] (aq)$

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