Complete the following equations and identify the incorrect products A, B and C.
${BeCl}_{2} + N_{2} O_{4} \overset{ethylacetate}{\to} A \overset{50^{\circ} C, Vacuum}{\to} B \overset{120^{\circ} C}{\to} C$

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$Be {({NO}_{3})}_{2} \cdot 2 N_{2} O_{4}, Be {({NO}_{3})}_{2}, {Be}_{4} O {({NO}_{3})}_{6}$

$Be {({NO}_{3})}_{2}, Be {({NO}_{2})}_{2}, BeO$

${BeCl}_{2} \cdot N_{2} O_{4}, Be {({NO}_{3})}_{2}, Be {({NO}_{3})}_{2}, Be {({NO}_{2})}_{2}$

$BeO, Be {({NO}_{2})}_{2}, Be {({NO}_{3})}_{2}$

answer is A, B, D.

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Detailed Solution

${BeCl}_{2} + 4 N_{2} O_{4} \to_{}^{Ethylacetate} \underset{(A)}{Be {({NO}_{3})}_{2}} \cdot 2 N_{2} O_{4} + 2 NOCl Be {({NO}_{3})}_{2} \cdot 2 N_{2} O_{4} \overset{50^{\circ} C, vaccume}{\to} Be {({NO}_{3})}_{2} + 2 N_{2} O_{4} ↑ 4 Be {({NO}_{3})}_{2} \overset{120^{\circ} C}{⟶} \underset{\underset{Basic Beryllium Nitrate}{(C)}}{{Be}_{4} O {({NO}_{3})}_{6}} + N_{2} O_{4} + 1 / 2 O_{2}$