Complete the following reaction and name the products A, B and C.
${\mathrm{CaC}}_2\stackrel{{\mathrm{H}}_2\mathrm{O}}{\to }\mathrm{A}\underset{\mathrm{tube}}{\overset{\text{ hot metal }}{\to }}\mathrm{B}\stackrel{{\mathrm{AlCl}}_3+{\mathrm{CH}}_3\mathrm{CI}}{\to }\mathrm{C}$

Equation-1
${\mathrm{CaC}}_2+2{\mathrm{H}}_2\mathrm{O}⟶\underset{\left(\mathrm{A}\right) \mathrm{Acetylene}}{{\mathrm{C}}_2{\mathrm{H}}_2}+\mathrm{Ca}(\mathrm{OH}{)}_2$
Hydrolysis of calcium carbide gives Acetylene
Equation-2
$3{\mathrm{C}}_2{\mathrm{H}}_2\underset{\mathrm{tube}}{\overset{ \mathrm{hot}metal}{\to }}\underset{\left(\mathrm{B}\right) \mathrm{Benzene}}{{\mathrm{C}}_6{\mathrm{H}}_6}$
Equation-3
${\mathrm{C}}_6{\mathrm{H}}_6+{\mathrm{CH}}_3\mathrm{Cl}\underset{-\mathrm{HCI}}{\overset{{\mathrm{AlCl}}_3}{\to }}\underset{\left(\mathrm{C}\right) \mathrm{Bethyl} \mathrm{Benzene}}{{\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_3}$
(or) ${\mathrm{CaC}}_2\stackrel{{\mathrm{H}}_2\mathrm{O}}{\to }\underset{\left(\mathrm{A}\right) \mathrm{Acetylene}}{{\mathrm{C}}_2{\mathrm{H}}_2}$
$\underset{\mathrm{metal} \mathrm{tube}}{\overset{\mathrm{Red} \mathrm{hot}}{\to }} \underset{\left(\mathrm{B}\right) \mathrm{Benzene}}{{\mathrm{C}}_6{\mathrm{H}}_6}$
$\underset{{\mathrm{AlCI}}_3}{\overset{{\mathrm{CH}}_3\mathrm{CI}}{\to }} \underset{\left(\mathrm{C}\right) \mathrm{Methyl} \mathrm{Benzene}}{{\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_3}$