Complete the following reaction and name the products A, B and C.CaC2→H2OA→tube hot metal B→AlCl3+CH3CIC

Equation-1CaC2+2H2O⟶C2H2(A) Acetylene+Ca(OH)2Hydrolysis of calcium carbide gives AcetyleneEquation-23C2H2→tube hotmetalC6H6(B) BenzeneEquation-3C6H6+CH3Cl→-HCIAlCl3C6H5CH3(C) Bethyl Benzene(or) CaC2→H2OC2H2(A) Acetylene→metal tubeRed hot C6H6(B) Benzene→AlCI3CH3CI C6H5CH3(C) Methyl Benzene

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Complete the following reaction and name the products A, B and C.
${CaC}_{2} \overset{H_{2} O}{\to} A \to_{tube}^{hot metal} B \overset{{AlCl}_{3} + {CH}_{3} CI}{\to} C$

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Detailed Solution

Equation-1
${CaC}_{2} + 2 H_{2} O ⟶ \underset{(A) Acetylene}{C_{2} H_{2}} + Ca (OH)_{2}$
Hydrolysis of calcium carbide gives Acetylene
Equation-2
$3 C_{2} H_{2} \to_{tube}^{hot metal} \underset{(B) Benzene}{C_{6} H_{6}}$
Equation-3
$C_{6} H_{6} + {CH}_{3} Cl \to_{- HCI}^{{AlCl}_{3}} \underset{(C) Bethyl Benzene}{C_{6} H_{5} {CH}_{3}}$
(or) ${CaC}_{2} \overset{H_{2} O}{\to} \underset{(A) Acetylene}{C_{2} H_{2}}$
$\to_{metal tube}^{Red hot} \underset{(B) Benzene}{C_{6} H_{6}}$
$\to_{{AlCI}_{3}}^{{CH}_{3} CI} \underset{(C) Methyl Benzene}{C_{6} H_{5} {CH}_{3}}$