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Q.

Complete the reaction:


<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>2</mn><msub><mi>NaHCO</mi><mn>3</mn></msub><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><msub><mi>SO</mi><mn>4</mn></msub><mo>&#x2192;</mo><mo>&#xA0;</mo></math>

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a

  <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>Na</mi><mn>2</mn></msub><msub><mi>SO</mi><mn>4</mn></msub><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><mn>2</mn><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><mi mathvariant="normal">O</mi><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><mn>2</mn><msub><mi>CO</mi><mn>2</mn></msub></math>

b

<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>Na</mi><mn>2</mn></msub><msub><mi>SO</mi><mn>4</mn></msub><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><msub><mi mathvariant="normal">O</mi><mn>2</mn></msub><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><msub><mi>CO</mi><mn>2</mn></msub></math>

c

<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>Na</mi><mn>2</mn></msub><msub><mi>SO</mi><mn>4</mn></msub><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><mi mathvariant="normal">O</mi><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><msub><mi mathvariant="normal">O</mi><mn>2</mn></msub></math>

d

<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>Na</mi><mn>2</mn></msub><msub><mi>SO</mi><mn>4</mn></msub><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><msub><mi mathvariant="normal">H</mi><mn>2</mn></msub><mi mathvariant="normal">O</mi><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><mn>3</mn><msub><mi mathvariant="normal">O</mi><mn>2</mn></msub></math> 

answer is A.

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Detailed Solution

Concept- The reaction between equimolar amount acid and base is known as the neutralisation reaction as they both cancel out each other’s effect.
Now the given reactants are a base sodium hydrogen carbonate, NaHCO3 and an acid, sulphuric acid, H2SO4. The products obtained after the neutralisation reaction are salt and water.
Thus, when sodium bicarbonate reacts with sulphuric acid, then the products are sodium sulphate, water and carbon dioxide.
Question ImageDue to the release of carbon dioxide, effervescence is observed in this reaction.
Hence, the correct answer is 1.
 
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Complete the reaction: