Compound 'A' undergoes following sequence of reactions to give compound 'B'. The correct structure and chirality of compound 'B' is:
[where Et is – $\left.-{\mathrm{C}}_2{\mathrm{H}}_5\right]$

Structure and Chirality of Compound B

Sequence of Reactions:

1. Isopropyl bromide (CH₃CHBrCH₃) is treated with Mg in ether to form the Grignard reagent (CH₃CH(MgBr)CH₃).
2. The Grignard reagent then reacts with D₂O, replacing the MgBr group with deuterium (D) to yield 2-deuteropropane (CH₃CHDCH₃).

Structure:

Product: CH₃–CH(D)–CH₃ (2-deuteropropane)

Chirality:

The carbon with the deuterium (D) atom has two identical methyl (CH₃) groups, one hydrogen (H), and one deuterium (D).
This carbon is not chiral because it does not have four different groups.