Compound(X), $C_{4} H_{8} O$ decolorises Baeyer’s reagent. It undergoes hydrolysis on reaction with $dil . H_{2} {SO}_{4}$ and produces (Y) and (Z). Both (Y) and (Z) give iodoform test positive. Only (Y) gives Tollen’s test positive. Choose the correct statement(s)-

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$[Y] \to_{}^{aq . NaOH (10 %)} {CH}_{3} - CH = CH - CHO$

$[Z] \to_{}^{PCC} [Y]$

$[X] \to_{2) Zn, H_{2} O}^{1) O_{3}} [Y] + Other product$

answer is A, B, C.

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Detailed Solution

$Y : C H_{3} - C H = O$

$X : C H_{2} = C H - O - C H_{2} C H_{3}$

$Z : C H_{3} - C H_{2} O H$

$C H_{3} C H_{2} O H \overset{D C C}{\to} C H_{3} C H O$

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