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Q.

Compounds ‘A’ and 'B' react according to the following chemical equation :

A(g)+2B(g)2C(g)

Concentration of either ‘A’ or 'B' were changed keeping the concentration of one of the reactants
constant and rates were measured as function of initial concentration. Following results were obtained.
Choose the Correct option for this reaction.

Experi-

ment

Initial

concentration

of [A]/molL1

Initial

concentration

of [B]/molL1

Initial

concentration

of [C]/molL1

1.0.300.300.10
2.0.300.600.40
3.0.600.300.20

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a

 Rate =k[A][B]

b

 Rate =k[A]2[B]

c

 Rate =k[A]2[B]0

d

 Rate =k[A][B]2

answer is B.

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Detailed Solution

Suppose order with respect to A and B are r and y respectively.

 Rate =k[A]x[B]y

For experiment 1,

0.1=k(0.3)x(0.3)y        …..(i)

For experiment 2,

0.4=k(0.3)x(0.6)y        ….(ii)

For experiment 3,

0.2=k(0.6)x(0.3)y        …..(iii)

Dividing equation (ii) by (i)

0.40.1=(0.6)y(0.3)y

      y = 2

Dividing equation (iii) by (i)

0.20.1=(0.6)y(0.3)y

     x = 1

Rate law

Rate = k[A] [B]2

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