Compounds                                                            Numbers of isomers

	Column -I		Column -II
A)	Number of diastereomers of $C_{2}FClBrI$	p)	4
B)	Number of stereoisomers of	q)	8
C)	Number of isomeric alcohols of ${\mathrm{C}}_4{\mathrm{H}}_{10}\mathrm{O}$	r)	6
D)	Number of isomeric esters of ${\mathrm{C}}_4{\mathrm{H}}_8{\mathrm{O}}_2$	s)	2

The bicyclic compound has two substituents.

Each substituent can independently be above or below the plane, giving 2² = 4 stereoisomers.

Correct match: s = 2

Alcohols with the formula C₄H₁₀O include:

• 1-butanol
• 2-butanol (2 enantiomers)
• 2-methyl-1-propanol
• 2-methyl-2-propanol

Total number of isomeric alcohols = 6.

Correct match: p = 4

Possible esters include:

• Methyl propanoate
• Ethyl ethanoate
• Propyl formate
• Butyl formate

Total number of isomeric esters = 2.

Correct match: p = 4

Option a:

• A → r ✅
• B → s ✅
• C → p ✅
• D → p ✅

This matches Option A perfectly.