Concentrated Aqueous solution sulphuric acid $98\% {\mathrm{H}}_2{\mathrm{SO}}_4$ by mass and has a density of $1.80 \mathrm{g}.{\mathrm{mL}}^{-1}.$ Volume of acid required to make $1$ litre of $0.1 \mathrm{M} {\mathrm{H}}_2{\mathrm{SO}}_4$ solution

${\mathrm{H}}_2{\mathrm{SO}}_4$ is $98\%$ by weight

wt. of ${\mathrm{H}}_2{\mathrm{SO}}_4=98 \mathrm{gm}$

wt. of solution $= 100 \mathrm{gm}$

$\therefore$  Volume of solution $=\frac{100}{1.80}\mathrm{mL}=\frac{100}{1.80\times 1000}\text{ litre }$

$\therefore M_{{\mathrm{H}}_2{\mathrm{SO}}_4}=\frac{98}{98\times \frac{100}{1.80\times 1000}}=18.014$

Let $\mathrm{V} \mathrm{mL}$ of this ${\mathrm{H}}_2{\mathrm{SO}}_4$ are used to prepare 1 litre of $0.1 \mathrm{M} {\mathrm{H}}_2{\mathrm{SO}}_4$ solution. 

$\begin{array}{l}{M}_1{V}_1=M_2{V}_2\Rightarrow V\times 18.014=1000\times 0.1\\ V=5.55\mathrm{mL}\end{array}$