Concentration of a reactant $\text{'}A\text{'}$  is changed from $0.044\text{M}$ to $0.032\text{M}$ in 25 minutes, the average rate of the reaction during this interval is

Given values are ;

Concentration of a reactant ‘A’ is changed from 0.044 M to 0.032 M and time (dt) = 25 minutes

$\text{Average}\text{rate}\text{=}\frac{dc}{dt}$

Where, dc = change in concentration of A

dt = Time taken for the change units of concentration = mole/litre

Units of time = minutes

                       $=\frac{0.044-0.032}{25}$

                       $=0.00048\text{mole}{\text{.lit}}^{\text{-1}}{\text{min}}^{-1}$

                       $=4.8\times {10}^{-4}\text{mole}{\text{.lit}}^{\text{-1}}{\text{min}}^{-1}$