Concentration of reactant 'A' is changed from 0.044 M to 0.032M in 25 minutes, the average rate of the reaction during this interval is

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0.0048 mole/lit/min

0.00048 mole/lit/sec

$4.8 \times 10^{- 4}$ mole/lit/min

0.0048 mole/lit/sec

answer is C.

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Detailed Solution

$Average rate = \frac{0.044 - 0.032}{25} = \frac{0.012}{25} = 4.8 \times 10^{- 4} mole / lit / \min Average rate = \frac{4.8 \times 10^{- 4}}{60} = 8 \times 10^{- 6} mole / lit / \sec$

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