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Q.

$Conc. H_{2} {SO}_{4}$ reacts with $C_{2} H_{5} OH at 170^{\circ} C$ to form

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a

${CH}_{3} CHO$

b

$C_{2} H_{4}$

c

${CH}_{3} {COCH}_{3}$

d

${CH}_{3} COOH$

answer is D.

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Detailed Solution

$\underset{Ethanol}{C_{2} H_{5} OH} \to_{170^{0} C}^{conc . H_{2} {SO}_{4}} \underset{Ethene}{C_{2} H_{4}} + H_{2} O$

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