Condensation product of the benzaldehyde and acetophenone in alkaline medium at 293k is

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$C_{6} H_{5} - C H_{2} - C O - C H_{2} - C_{6} H_{5}$

$C_{6} H_{5} - C H = C H - C O - C_{6} H_{5}$

$C_{6} H_{5} - C H_{2} - C_{6} H_{4} - C O - C H_{3}$

$C_{6} H_{5} - C O - C H_{2} - C_{6} H_{4} - C H_{3}$

answer is C.

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Detailed Solution

Condensation product of Benzaldehyde and Acetophenone at 293K in presence of an alkaline medium like $N a O H$

This is an example of Cross Aldol Condensation. It occurs in aldehydes and ketones having alpha hydrogen atom to give hydroxy aldehydes called aldols and if condensation occurs between two different aldehydes and/or ketones is called Cross Aldol Condensation.

$C_{6} H_{5} C H O + C H_{3} C O C_{6} H_{5} \overset{N a O H}{\to} C_{6} H_{5} - C H = C H - C O - C_{6} H_{5}$