Condenser A has a capacity of 15 $μ$ F when it is filled with a medium of dielectric constant 15. Another
condenser B has a capacity of 1 $μ$ F with air between the plates. Both are charged separately by a battery of 100 V. After charging, both are connected in parallel without the battery and the dielectric medium being removed. The common potential now is

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1600 V

400 V

1200 V

800 V

answer is B.

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Detailed Solution

Charge, $q_{1} = C_{1} V = (15) \times 100 = 1500 μC$

Charge, $q_{2} = C_{2} V = (1) \times 100 = 100 μC$

$∴$ Net charge, $q_{net} = q_{1} + q_{2} = 1600 μC$

When dielectric is removed, $C'_{1} = \frac{C_{1}}{K} = \frac{15}{15} = 1 μF$

Now, common potential, $V = \frac{q_{net}}{C'_{1} + C_{2}} = \frac{1600}{1 + 1} = 800 V$

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