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Q.

Conductivity of 1 M KCl  solution is 1.29 S m-1 and its resistance is 100 ohms. Conductivity of 0.2 M KCl solution whose resistance is 520 ohms will be

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a

2.48 S cm1

b

0.248 S m1

c

0.248 S cm1

d

2.48 S m1

answer is B.

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Detailed Solution

The cell constant is given by the equation: 
Cell constant,
 G= conductivity × resistance       =1.29S/m×100Ω      =129m1=1.29cm1
Conductivity of 0.2 mol L-1 KCI solution
         cell constant/ resistance =GR=129m1520Ω=0.248Sm1
 

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