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Q.

Conductivity of a saturated solution of a sparingly soluble salt AB at 298K is 

1.85 × 10–6Sm–1. Solubility product of the salt AB at 298 K is 
 given λM0(AB)=1.4×104Sm2mo11

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a

1.74 × 10-12

b

7.5×10–12

c

1.32×10–12

d

5.7×10–12

answer is D.

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Detailed Solution

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m =k ×1000C  1.40×10-4  =1.85×10-2×11000C(units are in meters) C= 1.32 ×10-6 ABA++B- Ksp=C2= (1.321 ×10-6)=1.74×10-12M2.

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Conductivity of a saturated solution of a sparingly soluble salt AB at 298K is 1.85 × 10–6Sm–1. Solubility product of the salt AB at 298 K is  given λM0(AB)=1.4×10−4Sm−2mo1−1