Conical vessel whose internal dimensions are 105 cm deep and 120 cm in diameter is full of water. If a cubic decimeter of water weight 1 kg 500g. The weight of water contained in the vessel is

For a conical vessel,

Height , h$=105$ cm

Base diameter, $d=120$

$r=\frac{d}{2}=\frac{120}{2}=60$  cm

Weight of 1 cubic decimeter of water $=$ 1 kg 500g

Volume of water in vessel $=\frac{1}{3}\pi r^{2}h$

$=\frac{1}{3}\times \frac{22}{7}\times 60\times 60\times 105$

$=22\times 3600\times 5$

$=22\times 18000$

$=396000{\text{ cm}}^3$

$=396\times {10}^3{\text{ cm}}^3$

Total cut of water in vessel $=396\times 1kg500kg$

$=594kg$