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Q.

Consider 100% ionized
$A) 0.1 M C o C l_{3} \cdot 6 N H_{3}$
$B) 0.15 M C o C l_{3} . 5 N H_{3}$
AgCl is precipitated by adding excess ${AgNO}_{3}$ solution to A and B separately. The correct relation of moles of AgCl precipitated will be

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a

A = B

b

1.5 A = B

c

A = 2B

d

2A = B

answer is A.

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Detailed Solution

$[Co {({NH}_{3})}_{6}] {Cl}_{3} ⇌ {[Co {({NH}_{3})}_{6}]}^{3 +} + 3 {Cl}^{-} 0.1 M 0.3 M$

$[Co {({NH}_{3})}_{5} Cl] {Cl}_{2} ⇌ {[Co {({NH}_{3})}_{5} Cl]}^{2 +} + 2 {Cl}^{-} 0.15 M 0.3 M$

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