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Q.

Consider 100ml of 0.3 molar solution formed by dissolving 3.33g of $X C l_{2}$ in water. Molar mass of element X?

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a

87

b

24

c

40

d

111g

answer is C.

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Detailed Solution

$M = \frac{w_{s o l u t e}}{G M W_{s o l u t e}} \times \frac{1000}{V_{s o l u t e} i n m l}$

$M W_{x} + 71 = 111$

x = 40

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