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Consider 2 balls A and B of the same mass. The potential energy of ball A is thrice that of ball B. How high is ball A compared to ball B?

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Twice as high height as ball B

Same height as ball B

Four times as high height as ball B

Thrice as high height as ball B

answer is D.

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Detailed Solution

PE_A = (m x g x h)_A

PE_B = (m x g x h)_B

m_A = m_B = m

g_A = g_B = g

PE_A = 3 x PE_B

m_A x g_A x h_A = m_B x g_B x h_B x 3

m x g x h_A = m x g x h_B x 3

h_A = 3 x h_B

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