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Q.

Consider a binary mixture of volatile liquids. If at $X_{A} = 0.4$ the vapour pressure of solution is 580 torr then the mixture could be ( $p_{A}^{o} = 300$ torr, $p_{B}^{o} = 800 torr$ ):

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a

${nC}_{6} H_{14} - {nC}_{7} H_{16}$

b

${CHCl}_{3} - {CH}_{3} {COCH}_{3}$

c

$C_{6} H_{6} - C_{6} H_{5} {CH}_{3}$

d

$C_{6} H_{5} Cl - C_{6} H_{5} Br$

answer is A.

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Detailed Solution

It shows negative deviation from Raoult's law

$p_{s}$ (actual) = 580 torr

$p_{s}$ (Raoult) $= 0.4 \times 300 + 0.6 \times 800 = 600$ torr.

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Consider a binary mixture of volatile liquids. If at XA=0.4 the vapour pressure of solution is 580 torr then the mixture could be (pAo=300 torr, pBo=800 torr):