Consider a binary solution of two volatile liquid components, 1 and 2. x₁ and y₁ are the mole fractions of component 1 in liquid and vapour phases, respectively. The slope and intercept of the linear plot of $\frac{1}{x_{1}} vs \frac{1}{y_{1}}$ Are given respectively as :

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\frac{P_{1}^{0}}{P_{2}^{0}}, \frac{P_{1}^{0} - P_{2}^{0}}{P_{2}^{0}}$

$\frac{P_{2}^{0}}{P_{1}^{0}}, \frac{P_{2}^{0} - P_{1}^{0}}{P_{2}^{0}}$

$\frac{P_{1}^{0}}{P_{2}^{0}}, \frac{P_{2}^{0} - P_{1}^{0}}{P_{2}^{0}}$

$\frac{P_{2}^{0}}{P_{1}^{0}}, \frac{P_{1}^{0} - P_{2}^{0}}{P_{2}^{0}}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$∵$ For liquid solution of two liquids ‘1’ and ‘2’

$\begin{array}{l} P_{1} = P_{T} y_{1} = P_{1}^{\circ} x_{1} \\ ∴ \frac{P_{T}}{x_{1}} = \frac{P_{1}^{\circ}}{y_{1}} \\ ∴ \frac{P_{2}^{\circ} + x_{1} (P_{1}^{\circ} - P_{2}^{\circ})}{x_{1}} = \frac{P_{1}^{\circ}}{y_{1}} \\ \begin{array}{l} ∴ \frac{P_{2}^{\circ}}{x_{1}} + (P_{1}^{\circ} - P_{2}^{o}) = \frac{P_{1}^{\circ}}{y_{1}} \\ ∴ \frac{1}{x_{1}} = (\frac{P_{1}^{o}}{P_{2}^{o}}) (\frac{1}{y_{1}}) + (\frac{P_{2}^{o} - P_{1}^{o}}{P_{2}^{\circ}}) \\ ∴ Slope = (\frac{P_{1}^{o}}{P_{2}^{o}}) \\ ∴ Intercept = (\frac{P_{2}^{o} - P_{1}^{o}}{P_{2}^{o}}) \end{array} \end{array}$