Consider a dipole with dipole moment 4.8 x 10-30 cm. Let a point P lies 4.1 x 10-9 m away from centre of dipole. Match the values of potentials given in column-II with column-I and mark the correct choice from the given codes. Column-I Column-IIi.Point is along axis of dipole nearer to positive-charge:p.-1.8 X 10-3 Vii.Point is 45° above the axis but nearer to positive charge.q.1.8 X 10-3 Viii.Point is 45° above the axis but nearer to negative charge.r.2.6x 10-3 VCodes:

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Consider a dipole with dipole moment 4.8 x 10^-30 cm. Let a point P lies 4.1 x 10^-9 m away from centre of dipole. Match the values of potentials given in column-II with column-I and mark the correct choice from the given codes.

	Column-I		Column-II
i.	Point is along axis of dipole nearer to positive-charge:	p.	-1.8 X 10^-3 V
ii.	Point is 45° above the axis but nearer to positive charge.	q.	1.8 X 10^-3V
iii.	Point is 45° above the axis but nearer to negative charge.	r.	2.6x 10^-3 V

Codes:

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i-q, ii-p, iij-r

i-p, ii-r, iii-q

i-r, ii-q, iii-p

i-q, ii-r, iii-p

answer is C.

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Detailed Solution

$\begin{array}{rcl} (i) V & = & \frac{9 \times 10^{9} \times 4.8 \times 10^{- 30} \times \cos 0 °}{{(4.1 \times 10^{- 9})}^{2}} = 2.6 \times 10^{- 3} V \\ (ii) V & = & \frac{kpcosθ}{r^{2}} = 1.8 \times 10^{- 3} V \\ (iii) V & = & \frac{1}{4 {πε}_{0}} \cdot \frac{pcosθ}{r^{2}} \\ = & \frac{9 \times 10^{9} \times 4.8 \times 10^{- 30} \times \cos 135 °}{{(4.1 \times 10^{- 9})}^{2}} \\ = & - 1.8 \times 10^{- 3} V \end{array}$