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Q.

Consider a dipole with dipole moment 4.8 x 10-30 cm. Let a point P lies 4.1 x 10-9 m away from centre of dipole. Match the values of potentials given in column-II with column-I and mark the correct choice from the given codes.
 

 Column-I Column-II
i.Point is along axis of dipole nearer to positive-charge:p.-1.8 X 10-3 V
ii.Point is 45° above the axis but nearer to positive charge.q.1.8 X 10-3 V
iii.Point is 45° above the axis but nearer to negative charge.r.2.6x 10-3 V

Codes:

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a

i-p, ii-r, iii-q
 

b

i-q, ii-p, iij-r
 

c

i-r, ii-q, iii-p

d

i-q, ii-r, iii-p

answer is C.

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Detailed Solution

 (i) V=9×109×4.8×10-30×cos0°4.1×10-92=2.6×10-3 V (ii) V=kpcosθr2=1.8×10-3 V (iii) V=14πε0·pcosθr2 =9×109×4.8×10-30×cos135°4.1×10-92 =-1.8×10-3 V

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