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Q.

Consider a hydrogen atom with its electron in the nth orbit. An electromagnetic radiation of wavelength 90nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4eV, then the value of n is (take hc=1242eV-nm)

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answer is 2.

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Detailed Solution

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EinceV=1242eV-nmλnm=124290=13.8eV

Energy of the electron=−13.6eVn2+13.8=0+10.4eV

=−13.6eVn2=−3.4eV

=n2=13.6eV3.4eV=4⇒n=2

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