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Q.

Consider a long cylindrical wire of radius R having uniform current density J=J0k^. Axis of this cylindrical wire is along z-axis. A cylindrical wire of radius (R4) is removed from the cylindrical wire which lead to a cavity. (Axis of this cavity is parallel to z-axis which is passing through the point O'(4,3). Cross sectional view of the wire is shown in diagram. On the basis of above paragraph answer the following questions

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Detailed Solution

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Magnetic field inside the cavity is uniform
B=μ0J02(OO)3i^+4j^5B=μ0J02(5)3i^+4j^5B=μ0J02(3i^+4j^)
For No collision
R0R42mv0μ0J0qR4v00J0q8mv00J08

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