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Q.

Consider a non – stoichiometric compound $C u_{1.90}$ due to metal deficient defect. Calculate the value of molar ratio of $C u^{+}$ and $C u^{+ 2}$ ions in the compound.

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answer is 18.

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Detailed Solution

Let $x$ atoms are in $+ 2$ state

$x \times 2 + (1.90 - x) 1 - 2 = 0, x = 0.1$

$\frac{n_{C u} + 2}{n_{C u} + 1} = \frac{0.1}{1.90 - 0.1} = \frac{1}{18} \Rightarrow \frac{n_{C u} + 1}{n_{C u} + 2} = 18$

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