Consider a reaction $A (g) \to 3 B (g) + 2 C (g)$ with rate constant is $1.386 \times 10^{- 2} \min^{- 1}$ in a non-rigid closed container starting with 2 moles of A in 12.5 L vessel initially, if reaction is allowed to take place at constant pressure and at 298 K the conc. of B after 100 min is

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0.189 M

0.033 M

0.9 M

0.665 M

answer is D.

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Detailed Solution

$A \to 3 B + 2 C$

$Rate = K [A] = 1.386 \times 10^{- 2} \times \frac{2}{12.5} = 2.2176 \times 10^{- 3} mol . L^{- 1} \min^{- 1} Rate = \frac{1}{3} \times \frac{d [B]}{dt} 2.2176 \times 10^{- 3} = \frac{1}{3} \times \frac{d [B]}{100} {[B]}_{t} = 0.665 M$

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