Consider a set of six infinite long straight parallel wires arranged perpendicular to the plane of paper in a hexagon as shown. The length of the each side of the hexagon is 3cm.What is the magnitude and direction of the magnetic field at point P? (Twelve direction at consecutive equal angles have been shown, give your answer in forms of their respective numbers).

Resultant magnetic field produced by the conductors each carrying a current of $\sqrt{3} A is B_1=\frac{2\times {\mu }_0.\sqrt{3}.}{2\mathrm{\pi }.3\times {10}^{-2}}T=\frac{4\times {10}^{-5}}{\sqrt{3}}T and \overrightarrow{B_1} acts along 10.$

Resultantmagnetic field produced by the other pair of conductors each carrying a current $\sqrt{3} A$is $B_2 =\frac{2.{\mu }_0.\sqrt{3}}{2\mathrm{\pi }.3\times {10}^{-2}}T=\frac{4}{\sqrt{3}}\times {10}^{-5} T and \overrightarrow{B_2} acts along 8.$

Resultant magnetic field produced by the pair of conductors each carrying a current of $\sqrt{2} A is zero .$

Therefore net magnetic field produced by all six conductors at the centre of the hexagon 

= $\sqrt{{\left(B_1\right)}^2+{\left(B_2\right)}^2+2.B_1.B_2.\cos {60}^0} = \frac{4\sqrt{3}}{\sqrt{3}}\times {10}^{-5} T=40\times {10}^{-6} T$