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Consider a solenoid with magnetic field 0.3 T inside it. A 8 cm long wire is placed inside the solenoid perpendicular to its axis. Find the magnetic force acting on the wire if the wire carries 10 A current.

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0.14 N

0.24 N

0.34 N

0.44 N

answer is B.

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Detailed Solution

$F = I l B \sin θ$

$Here, θ = 90^{\circ}, I = 10 A,$

$l = 8 cm = 8 \times 10^{- 2} m, B = 0.3 T$

$∴ F = 10 \times 8 \times 10^{- 2} \times 0.3 \times \sin 90^{\circ} = 0.24 N$

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