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Consider a spectral line resulting from the transition n = 5 to n = 1, in the atoms and ions given below. The shortest wavelength is produced by

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helium atom

deuterium atom

singly ionized helium

ten times ionized sodium atom

answer is D.

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Detailed Solution

$\frac{1}{λ} = {RZ}^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$

So the wavelength will be shortest for the ion with highest atomic number. Here it is ten times ionized sodium atom.

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