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Q.

Consider a sphere of mass 'm'radius 'R' doing pure rolling motion on a rough surface having velocity V0 as shown in the Figure. It makes an elastic impact with the smooth wall and moves back and starts pure rolling after some time again.

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a

Final velocity of ball will be 37V0

b

Moment of impulse provided by the wall during impact about O equals 2mv0R in magnitude.

c

Change in angular momentum about 'O' in the entire motion equals 2mv0R in magnitude.

d

Final velocity of ball will be -37V0

answer is A, B, D.

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Detailed Solution

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( at the point of pure rolling )
Taking angular momentum about the point P

Iω0-mV0R=Iω+mVR

25mR2×V0R-mV0R=25mR2×VR+mVR

V=-3V07

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