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Q.

Consider a system of two masses and a pulley shown in the figure. The coefficient of friction between the two blocks and also between block and table is 0.1. Find the force, F, that must be given to the 0.8 kg block such that it attains acceleration of 5m/s2. (Assume g=10m/s2)  

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a

6.9 N

b

7.8 N

c

6.4 N

d

7.1 N

answer is A.

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Detailed Solution

For 0.8kg block,

F-T-0.1(0.2)g-0.1(1)g=0.8(5) ⇒F-T=5.2..(1)

For 0.2kg block 

T-0.1(0.2)g=0.2(5) ⇒T=1.2...(2)

Using (2) in (1)

We get F=6.4N

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