Q.

Consider a uniformly charged hemispherical shell having charge per unit area σ. Find potential (in Volts) at point P due to the shell, R is the radius of shell. The distance of point P from the centre is R/2 (see diagram).  [Given σRε0=4 SI units]

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Detailed Solution

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The field from P to C will be perpendicular to line PC. Hence, potential at P = Potential at C.

K(σ×2πR2)R=VC         =14πε0×σ×2πRR=VC=σR0=2SI unit

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