Consider a uniformly charged hemispherical shell having charge per unit area $σ$ . Find potential (in Volts) at point P due to the shell, R is the radius of shell. The distance of point P from the centre is R/2 (see diagram). $[Given \frac{σR}{ε_{0}} =4 SI units]$

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Detailed Solution

The field from P to C will be perpendicular to line PC. Hence, potential at P = Potential at C.

$\frac{K ({σ×2πR}^{2})}{R} {=V}_{C} = \frac{1}{{4πε}_{0}} × \frac{σ×2πR}{R} {=V}_{C} = \frac{σR}{{2ε}_{0}} =2SI unit$

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