Consider a uniformly charged spherical surface with charge per unit surface area $σ$ . A small patch of small area dA is removed from it to create a hole (Given : Electric intensity due to a uniformly charged spherical thin shell is zero anywhere inside it and for external point, the charge on shell behaves like a point charge at the centre of the shell)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Field at locality of hole $= \frac{σ}{ε_{0}}$

Field at locality of hole $= \frac{σ}{2 ε_{0}}$

If now we try to put the patch to close the hole it experiences an outward force of $\frac{σ^{2}}{2 ε_{0}} (d A)$

If now we try to put the patch to close the hole it experiences an outward force of $\frac{σ^{2}}{ε_{0}} (d A)$

answer is A, C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$E_{1} + E_{2} = \frac{K Q}{R^{2}} = \frac{σ}{ε_{0}} E_{1} + E_{2} = 0 ∴ E_{1} = E_{2} = \frac{σ}{2 ε_{0}}$

JEE

NEET

Foundation JEE

Foundation NEET

CBSE