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Q.

Consider a wire carrying a steady current, I placed in a uniform magnetic field B perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do no work. This implies that,

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a

motion of charges inside the conductor is unaffected by B, since they do not absorb energy

b

some charges inside the wire move to the surface as a result of B

c

if the wire moves under the influence of B, no work is done by the magnetic force on the ions, assumed fixed within the wire.

d

if the wire moves under the influence of B, no work is done by the force

answer is B, D.

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Detailed Solution

Magnetic forces on  a wire carrying a steady current, I placed in a uniform magnetic field B perpendicular to its length is given by

      F=IlB

The direction of force is given by Flemings left hand rule and F is perpendicular to the direction of magnetic field and direction of I . Therefore, work done by the magnetic force on the ions is zero.

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