Consider a wire carrying a steady current, I placed in a uniform magnetic field B perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do no work. This implies that

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if the wire moves under the influence of B, no work is done by the force

motion of charges inside the conductor is unaffected by B since they donot absorb energy

if the wire moves under the influence of B, no work is done by the magnetic force on the ions, assumed fixed within the wire

some charges inside the wire move to the centre as a result of B

answer is D.

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Detailed Solution

As the force is perpendicular to the length of the wire, the work done by the force is zero, because charges are moving along the rod.

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