Consider a wire having current 10A having area of cross-section 1 cm2. If number of electrons per unit volume is 9×1028m−3. Find the drift velocity of electrons:

i=neAvdvd=ineAvd=6.94×10−6m/s

Consider a wire having current 10A having area of cross-section 1 cm2. If number of electrons per unit volume is 9×1028m−3. Find the drift velocity of electrons:

i=neAvdvd=ineAvd=6.94×10−6m/s

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Consider a wire having current 10A having area of cross-section 1 cm². If number of electrons per unit volume is $9 \times 10^{28} m^{- 3}$ . Find the drift velocity of electrons:

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$6.94 \times 10^{- 6} {ms}^{- 1}$

$2.94 \times 10^{- 4} {ms}^{- 1}$

$1.94 \times 10^{- 3} {ms}^{- 1}$

$5.94 \times 10^{- 2} {ms}^{-}$

answer is A.

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Detailed Solution

$i = n {eAv}_{d}$

$v_{d} = \frac{i}{n eA}$

$v_{d} = 6.94 \times 10^{- 6} m / s$

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Consider a wire having current 10A having area of cross-section 1 cm2. If number of electrons per unit volume is 9×1028m−3. Find the drift velocity of electrons:

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Consider a wire having current 10A having area of cross-section 1 cm². If number of electrons per unit volume is $9 \times 10^{28} m^{- 3}$ . Find the drift velocity of electrons: