Consider all possible permutations of the letters of the word ENDEANOEL. The number of permutations contacting the word ENDEA, is

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$5!$

$2 \times 5!$

$7 \times 5!$

$21 \times 5!$

answer is A.

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Detailed Solution

Taking ENDEA as one letter we have four more letters N, O, E, and L. These five letters can be arranged in $5!$ ways. So, the number of permutations contain the word ENDEA is $5!$

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