Q.

Consider an electric field  E=E0x^, where E0 is a constant. The flux through the area (as shown in the figure) due to this field is :

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a

2E0a22

b

2E0a2

c

2E0a2

d

E0a2

answer is C.

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Detailed Solution

Here, E=E0x^
In this problem, x^, y^ and z^ are the unit vectors along x, y and z axes respectively
Shaded area, A=PQ×QR
A=(0x^+ay^+0z^)×(ax^+0y^+az^)ϕ=EA=E0x^a2x^a2z^=E0a2

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