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Consider an endothermic reaction $X \to Y$ with the activation energies $E_{b}$ and $E_{f}$ for the backward and forward reactions, respectively. In general

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$E_{b} < E_{f}$

$E_{b} > E_{f}$

$E_{b} = E_{f}$

no definite relation

answer is A.

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Detailed Solution

The information in the question can be plotted in the given diagram:

So, from the diagram we can say that $E_{b} < E_{f}$ .

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