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Q.

Consider an imaginary ion $_{22}^{48} X^{3 -}$ . The nucleus contains ‘a’% more neutrons than the number of electrons in the ion. The value of ‘a’ is ____. [nearest integer]

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answer is 4.

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Detailed Solution

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$_{22}^{48} X^{3 -}$

No. of neutrons = 26

No. of electrons = 25

% of extra neutrons $= \frac{26 - 25}{25} \times 100 = 4$

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