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Q.

Consider Fraunhoffer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference (in radian) between the wavelets from the opposite edges of the slit is

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a

π/2

b

π/4

c

π

d

answer is D.

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Detailed Solution

For first minimum path difference is x = λ 
Hence phase difference is 2π.

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