Consider ‘n’ is the number of lone pair of electrons present in the equatorial position of the most stable structure of ${\mathrm{ClF}}_3$. The ions from the following with
‘n’ number of unpaired electrons are :
A. V³⁺
B. Ti³⁺
C. Cu²⁺
D. Ni²⁺
E. Ti²⁺
Choose the correct answer from the options given below :

ClF₃

n = 2 (No of lone pair present in equitorial plane)
                                                    (Unpaired e–)
(A) V⁺³ : [Ar]3d²                                2
(B) Ti³⁺ : [Ar]3d¹                                1
(C) Cu⁺² : [Ar]3d⁹                              1
(D) Ni⁺² : [Ar]3d⁸                               2
(E) Ti⁺² : [Ar]3d²                                2