Consider the above reaction where 6.1 g of benzoic acid is used to get 7.8 g of m-bromo benzoic acid. The percentage yield of the product is _______. Rounded off to the nearest integer (Given atomic masses C = 12, H = 1.0, O = 16.0, Br = 80.04 )

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answer is 78.

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Detailed Solution

(Given atomic masses C = 12, K = 1.0 , O = 16.0, Br = 80.04 )

Moles of benzoic acid $= \frac{6.1}{122}$ = moles of m-bromo benzoic acid.

So, weight of m-bromo benzoic acid $= \frac{6.1}{122} \times 201 g = 10.05 g$

$% y i e l d = \frac{a c t u a l w e i g h t}{T h e r e t i c a l w e i g h t} \times 100 = \frac{7.8}{10.05} \times 100 = 77.61 % = 78 %$

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