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Consider the cell $P t | H_{2} (p_{1} a t m) H^{+} (x_{1} M) | | H^{+} (x_{2} M) | H_{2} (p_{2} a t m) P t$ . The cell reaction will be spontaneous if

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$p_{1} = p_{2} a n d x_{1} < x_{2}$

$p_{1} = p_{2} a n d x_{1} > x_{2}$

$x_{1} = x_{2} a n d p_{1} > p_{2}$

$x_{1} = x_{2} a n d p_{1} < p_{2}$

answer is B, C.

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Detailed Solution

$E = \frac{- 0.06}{2} \log \frac{{[H^{+}]}_{a}^{2} R_{12}^{1} (c)}{{[H^{+}]}_{c}^{2} P_{2} (a)}$

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