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Q.

Consider the change in oxidation state of ‘X’ corresponding to different emf values as shown in the diagram below
Then the species undergoing disproportionation is

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a

$X O_{4}^{-}$

b

$X_{2}$

c

$X O_{3}^{-}$

d

$X O_{}^{-}$

answer is C.

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Detailed Solution

$X O_{3}^{-} \overset{1.4 V}{\to} X O^{-} \overset{1.49 V}{\to} X_{2}$

$E_{X O^{-}}^{o} = 1.49 - 1.4$

= + 0.09 V

The cell potential is positive and cell reaction spontaneous.
Therefore $X O_{}^{-}$ undergoes oxidation and reduction.

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