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Q.

Consider the circuit shown in figure. With switch S1 closed and the other two switches open, the circuit has a time constant 0.05 sec. With switch S2 closed and the other two switches open, the circuit has a time constant 2 sec. With switch S3 closed and the other two switches open, the circuit oscillates with a period T. Find T/5 (in sec).
(Take π2=10 )

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answer is 4.

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Detailed Solution

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t1=RC;t2=R/L LC=t1t2=0.1sec>T=2pie1LC  T5=4sec

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