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Consider the equilibrium obtained by electrically connecting zinc-amalgam (Zn(Hg)) and HgO electrodes in mercury cell, $Z n (H g) + H g O_{(s)} \underset{}{⇌} Z n O_{(s)} + H g_{(l)}$ Under this equilibrium what is the relation between the potential of the Zn(Hg) and HgO electrodes measured against the standard hydrogen electrode?

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Zn(Hg) electrode potential is equal to HgO electrode potential.

Zn(Hg) electrode potential is more than HgO electrode potential.

HgO electrode potential is more than Zn(Hg) electrode.

Cell voltage at above said equilibrium is 1.35 V.

answer is A.

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