Consider the following arrangement and choose the correct options.

For left hand compartment
$\begin{array}{l}0.2\mathrm{M}{\mathrm{Na}}_2{\mathrm{SO}}_4;{\mathrm{\pi }}_1=(0.2)\times \left(\mathrm{S}\right)\times \left(\mathrm{T}\right)\times 3\\ {\mathrm{\pi }}_1=(0.6)\left(\mathrm{S}\right)\left(\mathrm{T}\right)\text{ and for }0.15\mathrm{MKCl}\\ {\mathrm{\pi }}_1=\left(2\right)\times \left(\mathrm{S}\right)\times \left(\mathrm{T}\right)\times (0.15)\\ =(0.3)\left(\mathrm{ST}\right)\\ \therefore {\mathrm{\pi }}_1>{\mathrm{\pi }}_2\Rightarrow {\mathrm{Na}}_2{\mathrm{SO}}_4\end{array}$
Solution have higher osmotic pressure and water will flow from lower concentration to higher concentration.
$\Rightarrow$Water will flow from RHC to LHC