Consider the following arrangement of resistors the currents in various branches is shown. Select the correct alternative is
 

Equivalent resistance of circuit $=\frac{10\times 5}{10+5}\times 2+\frac{1}{3}$
${\mathrm{R}}_{\mathrm{eq}}=7 \mathrm{\Omega }$
 

$\therefore {\mathrm{i}}_1=\frac{21}{7}=3 \mathrm{A}$
Current distribution is shown in the diagram
$\therefore {\mathrm{i}}_2=1-2=-1\mathrm{A}$
${\mathrm{v}}_{\mathrm{A}}-{\mathrm{v}}_{\mathrm{B}}=1\mathrm{A}\times 10 \mathrm{\Omega }$
${\mathrm{v}}_{\mathrm{AB}}=10\mathrm{V}$